An engineer weighs a sample of mercury (ρ = 13.6 * 103 kg/m3) and finds that the weight of the sample is 6.0 n. what is the sample's volume? the acceleration of gravity is 9.81 m/s 2. answer in units of m3.

Given:

ρ = 13.6 x 10³ kg/m³, density of mercury

W = 6.0 N, weight of the mercury sample

g = 9.81 m/s², acceleration due to gravity.

Let V = the volume of the sample.

Then

W = ρVg

or

V = W / (ρg)

= (6.0 N) / [ (13.6 x 10³ kg/m³) * (9.81 m/s²) ]

= 4.4972 x 10⁻⁵ m³

Answer: The volume is 44.972 x 10⁻⁶ m³