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31 August, 19:45

Jason applies a force of 4.00 newtons to a sled at an angle 62.0 degrees from the ground. What is the component of force effective in pulling the sled horizontally along the ground?

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  1. 31 August, 22:06
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    If we consider that the surface wherein this box is located is frictionless in such a way that the friction does not affect its motion, we can calculate for the horizontal force by multiplying the force with the sine of the angle.

    x-component of force = (4 N) x (sin 62°)

    = 3.53 N
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