What is the work function of aluminium metal in kj/mol if light with = 290 nm is necessary to eject electrons?

Work function = hf0, where f is the frequency and h is the plank's constant,

but, f = c/λ, where c is the speed of light 2.998 * 10^8 m/s, and λ is the wavelength (290 nm) or 2.9 * 10^-7 M

Thus, f = (2.998 * 10^8) / (2.9*10^-7)

= 1.034 * 10^15 Hz

Therefore, Work function = (1.034*10^15) * (6.626 * 10^-34)

= 6.8513 * 10^-19 Joules

But, 1 mole = 6.022 * 10^23 particles

Therefore, 6.8513 * 10^-19 * 6.022*10^23

= 41.259 * 10^4 J/mol

but, 1 kJ = 1000 J

Therefore; 4.1259 * 10^2 kJ/mol