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9 September, 15:32

It takes 26.5 N to just pull a 72 kg sled across snow. What is the coefficient of friction?

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  1. 9 September, 17:01
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    Assuming g = 10, the weight of the sled is 720N.

    If it takes 26.5N to just pull the sled, then the frictional force f is 26.5N in the opposite direction.

    f = μ*720N

    26.5N = μ*720N

    μ = 26.5N/720N = 0.037 (2 s. f.)
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