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7 March, 07:34

Find the magnitude of the force needed to accelerate a 220 g mass with a⃗ = - 0.205 m/s2 i^+0.400 m/s2 j^.

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  1. 7 March, 07:48
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    As, Fr = m. a

    With mass in kg

    We have:

    m = 220g

    m = 0,22kg

    We have too:

    a = - 0,205m/s^2 i + 0,400m/s^2 j

    Remembering that "a" is in vector

    a = axi + ayj

    a = √ (ax^2 + ay^2)

    a = √ ((-0,205) ^2 + (0,400) ^2)

    a = √ (0,202025)

    a ~ 0,449 m/s^2

    Then,

    Fr = m. a

    Fr = 0,22. 0,449

    Fr ~ 0,09888 N

    Fr ~ 9,88. 10^ (-2) N
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