For typical rubber-on-concrete friction, what is the shortest time in which a car could accelerate from 0 to 60 mph? suppose that μs=1.00 and μk=0.80

The shortest time would be 2.0051 seconds or 2.01 seconds if rounded off to the nearest tens.

below is the solution:

ΣF = ma

⇔ μsmg + μkmg + μrmg = mΔv/t

⇔ t = Δv/[ (μs + μk + μr) g]

Δv = 80 - 0 = 80 mph ≈ 35.7632 m/s and g = 9.8 m/s²

t ≈ 2.0051