Ask Question
3 August, 14:50

A torque of 50 N*m acts on a wheel of moment of inertia 25 kg*m^2 for 4 s and then is removed.

b) How many revolutions does it make in 15 s if it starts at rest?

I found the angular acceleration, 2 rad/s^2, but I don't know how to find the amount of revolutions.

+2
Answers (1)
  1. 3 August, 15:24
    0
    You have to find the calculate the circumference first then you can just multiply the diameter by π, which is about 3.142. That gives you the distance for each revolution. Then you can multiply by the number of revolutions per minute.
Know the Answer?
Not Sure About the Answer?
Get an answer to your question ✅ “A torque of 50 N*m acts on a wheel of moment of inertia 25 kg*m^2 for 4 s and then is removed. b) How many revolutions does it make in 15 s ...” in 📙 Physics if there is no answer or all answers are wrong, use a search bar and try to find the answer among similar questions.
Search for Other Answers