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14 March, 23:46

A turbine blade rotates with angular velocity ω (t) = 8.00 rad/s - 0.20 rad/s3 t 2. what is the angular acceleration of the blade at t = 6.8 s?

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  1. 15 March, 00:07
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    Given: ω (t) = 8.00 - 0.2*t^2

    Differentiating both sides with respect to time we get:

    angular acceleration = α (t) = - 0.2 * 2 * t

    At t = 6.8 sec,

    angular acceleration = α (t) = - 0.2 * 2 * 6.8 = - 2.72 rad/s^2
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