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13 October, 09:45

How much heat is absorbed by a 39g iron skillet when its temperature rises from 15oC to 24oC?

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  1. 13 October, 13:32
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    To begin, your equation is Q=mc{triangle}T

    Q is the end heat in Joules

    m is the mass

    c is the specific heat

    and

    {triangle} T is the change in temperature

    Now that we have the equation down, we are trying to find the end heat.

    Your specific heat, I suspect is 0.450 J/g{degrees}C because its the specific heat of iron. Making your equation you'll get:

    Q = (39g) x (0.450 J/g{degrees}C) x (9{degrees}C)

    Multiplying it all you'll get:

    Q = 157.95J

    or

    157.95 Joules
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