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9 December, 02:59

You have a simple circuit that includes a resistance device of 50 ohms, and the current flowing through it is 2.0 amps. Solve for the potential difference of the batteries.

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  1. 9 December, 04:37
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    Using Ohm's Law, we have that

    V = I * R

    Where V is the voltage of the battery (potential difference)

    I is the current flowing through the resistance R

    V = 2 A * 50 ohms = 100 V
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