Show that the difference in volume across a first-order phase boundary is given

by ∆V = - ∆F/P.

Question

Physics

Marley Frazier

8 May, 08:18

Show that the difference in volume across a first-order phase boundary is given

by ∆V = - ∆F/P.

+1

Answers (1)

Know the Answer?

Arely Bolton · Answer 1

G as a function of P at constant T for liquid and solid phases. As we can see from the fundamental equation, dG = VdP - SdT, the free energy of a phase increases with pressure: If the two phases have different molar volumes

Show that the difference in volume across a first-order phase boundary is givenby ∆V = - ∆F/P.

Show that the difference in volume across a first-order phase boundary is given

by ∆V = - ∆F/P.