A stone that starts at rest free falls for 7.0 s. How far does the stone fall in this time?

Question

Physics

Vincent Travis

29 March, 15:36

A stone that starts at rest free falls for 7.0 s. How far does the stone fall in this time?

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Answers (1)

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Hailie Macias · Answer 1

Gravitational acceleration is approx 9.8 m/s

Time is 7s

a=9.8 m/s

t=7s

a = d/t^2

therefore:

d = a * t^2

d = 9.8 * 7^2

d = 9.8 * 49

d = 480.2 [m]