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23 March, 07:21

A 95 kg man lying on a surface of negligible friction shoves a 65 g stone away from himself, giving it a speed of 4.0 m/s. what speed does the man acquire as a result?

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Answers (2)
  1. 23 March, 08:02
    0
    We can solve this problem by conserving linear momentum.

    We have then that:

    P1 = P2

    m1v1 + m2v2 = m1v1 ' + m2v2'

    Substituting values and clearing:

    95 (0) + 0.065 (0) = 95v + 0.065 (4)

    0 = 96v + 0.26

    96v = - 0.26

    v = - 0.0027 m / s

    The man moves in the opposite direction to the stone.

    answer:

    the speed that a man acquire as a result is v = - 0.0027 m / s
  2. 23 March, 08:54
    0
    Total momentum of the system must stay constant, so M1*V1 = - M2*V2. Substituting in the values and rearranging, we find - V2 = M1*V1 / M2. 65 grams = 0.065 kg, so

    0.065kg * 4.0m/s / 95kg = - 2.7*10^-3 m/s. The negative indicates he is travelling in the opposite direction as the stone. Speed is independent of direction, so the final answer is 2.7*10^-3 m/s.
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