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5 December, 15:36

A 0.065-kg tennis ball moving to the right with a speed of 15 m/s is struck by a tennis racket, causing it to move to the left with a speed of 15 m/s. if the ball remains in contact with the racquet for 0.020 s, what is the magnitude of the average force exerted on the ball?

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  1. 5 December, 18:36
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    Using the formula for impulse, we can solve this problem.

    In terms of change in momentum, impulse is:

    I = m (v2 - v1)

    Or in terms of force and contact time:

    I = F t

    Equating the two equations:

    m (v2 - v1) = F t

    Setting the right direction as positive and the left as negative, we can then substitute values with their respective signs:

    0.065 (-15 - 15) = F (0.020)

    F = - 97.5 N

    The negative sign indicates that the force was directed to the left.
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