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25 January, 20:33

A hydrogen atom is in its n = 2 excited state when its electron absorbs a photon of energy 8.5 ev. what is the kinetic energy of the resulting free electron?

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  1. 25 January, 22:39
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    The formula for determining the kinetic energy of free electron is,

    KE = - V (1/n^2)

    In this item, V is equal to 8.5 eV, n is equal to 2.

    Substituting the known values from the given above,

    KE = (-8.5 eV) (1/2^2)

    KE = - 2.125 eV

    Answer: - 2.125 eV
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