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31 May, 21:56

Light traveling through air at 3.00 · 10^8 m/s reaches an unknown medium and slows down to 2.00 · 10^8 m/s. What is the index of refraction of that medium? n =

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  1. 31 May, 22:52
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    V 1 = 3.00 · 10^8 m/s

    v 2 = 2.00 · 10^8 m/s

    The index of refraction:

    n = v 1 / v 2 = 3.00 · 10^8 m/s : 2.00 · 10^8 m/s = 1.5

    Answer:

    The index of refraction of that medium is 1.5
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