Light traveling through air at 3.00 · 10^8 m/s reaches an unknown medium and slows down to 2.00 · 10^8 m/s. What is the index of refraction of that medium? n =

Question

Physics

Alvin Dickerson

31 May, 21:56

Light traveling through air at 3.00 · 10^8 m/s reaches an unknown medium and slows down to 2.00 · 10^8 m/s. What is the index of refraction of that medium? n =

+3

Answers (1)

Know the Answer?

Hicks · Answer 1

V 1 = 3.00 · 10^8 m/s

v 2 = 2.00 · 10^8 m/s

The index of refraction:

n = v 1 / v 2 = 3.00 · 10^8 m/s : 2.00 · 10^8 m/s = 1.5

Answer:

The index of refraction of that medium is 1.5