A ball is hit straight up with an initial speed of 28 meters per second. What is the speed of the ball 2.2 seconds after it is hit? [Neglect friction.]

By neglecting friction, the final velocity of the ball thrown upward with an initial speed of v₀ can be calculated through the equation,

vf = v₀ - gt

where vf is final velocity, g is acceleration due to gravity and t is time. Substituting,

vf = 28 m/s - (9.8 m/s²) (2.2. s)

vf = 6.44 m/s

Thus, the final velocity of the ball is approximately 6.44 m/s.