An airplane accelerates from a velocity of 21 m/s at the constant rate of 3.0 m/s over 535 m. 2 what is its final velocity?

Initial velocity, u = 21 m/s

Acceleration, a = 3.0 m/s²

Distance traveled, s = 535 m

Let v = the final velocity.

Use the formula

v² = u² + 2as

v² = (21 m/s) ² + 2 (3.0 m/s²) (535 m) = 3651 m²/s²

v = 60.42 m/s

Answer: 60.42 m/s