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5 July, 22:34

How many liters of 60% alcohol solution should be added to 40 liters of a 20% alcohol solution to make a 50% solution?

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  1. 6 July, 00:26
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    Exactly 80 liters of 20% are needed.

    Let quantity of 20% alcohol solution be added : x liters

    Here is the work:

    > x*20% + 40 * 50% = (x+40) * 30%

    > x*0.2 + 40*0.5 = (x+40) * 0.3 ... (converting percentages into decimal)

    > 0.2x + 20 = 0.3x + 12

    > 20-12 = 0.3x - 0.2x (Rearranging similar terms)

    > 8 = 0.1 x

    Hence x = 8/0.1

    Ans 80 Litres
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