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19 July, 23:53

Sin2A + sin2B - sin2C = 4cosA*cosB*cosC

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Answers (2)
  1. 20 July, 00:07
    0
    Inconclusive

    Explanation:

    Sin2A = Sin (A+A) = SinACosA + CosAsinA=2SinACosA

    Similarly

    Sin2B = 2SinBCosB

    Sin2C=2SinCCosC

    Adding all; we cannot arrive at the expression at the right.
  2. 20 July, 01:09
    0
    use sin2A as 2sinAcosA and solve
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