Suppose you have a date with your spouse. There are 5 movies you can choose to watch together: 1 drama, 2 action, and 2 comedy. For dinner, you can have 2 types of noodles, 3 types of salads, or 2 types of meat. What is the probability, assuming choosing dinner and a movie are independent events, that you choose a drama and have noodles for dinner? Round to the nearest thousandths.

Question

Social Studies

Norman

2 June, 03:12

Suppose you have a date with your spouse. There are 5 movies you can choose to watch together: 1 drama, 2 action, and 2 comedy. For dinner, you can have 2 types of noodles, 3 types of salads, or 2 types of meat. What is the probability, assuming choosing dinner and a movie are independent events, that you choose a drama and have noodles for dinner? Round to the nearest thousandths.

+5

Answers (1)

Know the Answer?

Marley Braun · Answer 1

0.4857

Explanation:

probality=no of possible events/total no of outcomes.

Here, no of movies=5

no of noodles=2

no of salads = 3

or meat=2

So or here denotes multiplication

Therefore total for number of salads or meat is-3+2=5

From the statement, choosing a dinner and movie are independent events.

So prob of drama is 1/5 (1 drama in total no of 5movies of drama, action&comedy)

Also, prob of noodles is 2/7 (2noodles in total no of 7 of noodles, salad&meat)

Therefore the probalitity of choosing dinner and a movie is = 1/5*2/7=0.4857