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5 March, 14:36

If log2 = 0.3010. log3 = 0.4771, log5 = 0.6990. calculate log15?

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  1. 5 March, 16:43
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    Log25 = log5 + log5

    = log (10/2) + log (10/2)

    = (log10-log2) + (log10-log2)

    = (1-0.3010) + (1-0.3010)

    = 0.6990 + 0.6990

    = 1.3980
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