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14 July, 15:17

A group of statistics students decided to conduct a survey at their university to find the average (mean) amount of time students spent studying per week. Assuming a population standard deviation of three hours, what is the required sample size if the error should be less than a half hour with a 99% level of confidence?

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  1. 14 July, 16:23
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    Answer: 240

    Formula:

    n = [ (z-value * sd) / E]^2

    where n = sample size,

    z-value will be 2.58 using a z-table to represent the 99% confidence interval

    sd (standard deviation) = 3

    E = 0.5

    Substituting the parameters into the formula n = [ (z-value * sd) / E]^2, we have,

    n = [ (2.58 * 3) : 0.5]²

    n = 239.63 approximately 240.
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