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12 January, 19:33

G (x) = ax2+24

For the function g defined above, a is a constant and g (4) = 8. What is the value of g (-4) ?

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  1. 12 January, 21:27
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    So, Im assuming the x2 is x², if so then the answer would be

    G (4)

    Ax²+24=8

    we replace the x with the value of 4 since we're given the answer

    A (4) ²+24=8

    and then we try and solve the equation, first we need to get rid of the square which is (4) ² thats the same as 4*4 thats equal to 16, so our equation would look like this

    A (16) + 24=8

    then we carry on to try an look for (A), we can start by getting the difference between 24 and 8 so we move it to the other side as a - 24 and get this

    16 (A) = 8 - 24

    which would basically be by adding a - 24 to both sides so we can get rid of the + 24, and we get the same equation as above

    16 (A) + 24 - 24 = 8 - 24

    16 (A) = - 16

    then we need look for (A) by dividing both sides to 16

    16 (A) / 16 = - 16/16

    and we get that (A) = - 1

    so with that now we can look for the value of G (-4)

    first we form our new equation with the value of A and the new value of G which is - 4, now since we are dealing with a square it doesnt matter if (x) its positive or negative since it doesnt really affect the previous result (4) ²=16 and (-4) ²=16, but for the sake of it lets try to do it

    G (-4)

    A (-1)

    ax²+24

    so we replace with the values already obtained (A) and (x)

    (-1) (-4) ²+24

    as stated before the

    (-1) (16) + 24

    and all thats left is this

    -16+24

    and the answer to the question would be 8
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