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5 May, 08:53

On a standardized exam, the scores are normally distributed with a mean of 300 and a standard deviation of 20. Find the z-score of a person who scored 315 on the exam.

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  1. 5 May, 11:27
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    Answer: 0.75

    Explanation:

    Mean (μ) = 300

    Standard deviation (σ) = 20

    Find the z-score of a person who scored 315 on the exam;

    Raw score (x) = 315

    Z = (raw score - mean) : standard deviation

    Z = (x - μ) : σ

    Z = (315 - 300) : 20

    Z = 15 : 20

    Z = 0.75
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