How would you make 500.00 ml of 1.50 m sulfuric acid from a stock bottle that is 10.0 m?

Remember this formula: C1V1=C2V2

C1 being the initial concentration

V1 being the initial volume

C2 being the final concentration

V2 being the final concentration

In this case we just plug and chug:

C1=10 M

V1=what we're looking for

C2=1.50 M

V2=500 mL

10*V1=1.5*500

V1=750/10 = 75 mL of 10 M sulfuric acid needed.

First get 400 mL DI water. Add 75 mL 10 M sulfuric acid. Then add enough DI water to get the final volume to 500 mL.