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9 January, 01:17

0 ml of a 1.20 m solution is diluted to a total volume of 228 ml. a 114-ml portion of that solution is diluted by adding 111 ml of water. what is the final concentration? assume the volumes are additive.

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  1. 9 January, 03:13
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    54.0 ml of a 1.2 m solution was diluted to a total volume of 228 ml

    USing dilution equation

    M1V1 = M2V2

    Where M1V1 is before dilution while M2V2 is after dilution.

    Therefore;

    M1 = 1.20 M, V2 = 54 ml,

    M2 = V2 = 228 ml

    1.20 M * 54 ml = M2 * 228 ml

    M2 = (1.2 * 54) / 228 ml

    = 0.2842 M

    0.2842 * 114 ml = M2 * (114 + 111)

    M2 = (0.2842 * 114) / 225

    = 0.143995

    = 0.144 M
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