35.5 grams of an unknown substance is heated to 103.0 degrees Celsius and then placed into a calorimeter containing 100.0 grams of water at 24.0 degrees Celsius. If the final temperature reached in the calorimeter is 29.5 degrees Celsius, what is the specific heat of the unknown substance?

Question

Chemistry

Evie Austin

17 February, 19:39

35.5 grams of an unknown substance is heated to 103.0 degrees Celsius and then placed into a calorimeter containing 100.0 grams of water at 24.0 degrees Celsius. If the final temperature reached in the calorimeter is 29.5 degrees Celsius, what is the specific heat of the unknown substance?

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Chace Howard · Answer 1

delta t for water = 29.5 - 24.0 = 5.5 C heat gained by water = 4.18 J/gC x 100.0 g x 5.5 C = 2300 J sp ht = J/m dt = 2300 J / (35.5 g x 73.5) = 0.89 J/gC