What volume of 10.0 M H2SO4 is required to prepare 4.0 L of 0.50 M H2SO4

The initial concentration of H2SO4 is 10M

Given that, it has a constant number of moles.

We can say n=n

So C1xV1=C2xV2

where C is concentration and V is volume

This gives us V1 = (C2V2) / C1=0.2L

So we need 0.2ml of 10M H2SO4

(We add 3.8L of distilled water to reach 4L)

M is a unit of concentration and can be written as mol/L

Btw what does M stand for?