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19 August, 17:38

How many milliliters of a 1.25 molar hydrochloric acid solution would be needed to react completely with 60 grams of calcium

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  1. 19 August, 20:55
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    2HCl + Ca = CaCl₂ + H₂

    n (HCl) = cv

    n (Ca) = m (Ca) / M (Ca)

    n (HCl) = 2n (Ca)

    cv=2m (Ca) / M (Ca)

    v=2m (Ca) / {cM (Ca) }

    v=2*60/{1.25*40}=2.4 L
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