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23 November, 12:12

How many grams of potassium iodide, KI, are required to make 2.0 L of a 0.1M solution

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  1. 23 November, 14:51
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    Volume = 2.0 L

    Molarity = 0.1 M

    Molar mass KI = 166.0028 g/mol

    mass = V x M x molar mass

    mass = 2.0 x 0.1 x 166.0028

    = 33.20056 g of KI
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