How many bromine atoms are present in 35.2 g of CH2Br2?

Because the symbol for bromine is Br and the make-up of the elements say that there are 2 bromine atoms, I'd assume that you would take 35.2 and multiply it by the 2 bromine atoms, resulting in 70.4 bromine atoms. But, I could very easily be wrong since I don't remember learning this in science.