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25 February, 05:15

If 29.50 ml of 0.175m nitric acid neutralizes 50.0 ml of ammonium hydroxide, what is the molarity of the base?

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  1. 25 February, 07:01
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    The molarity of the base (ammonium hydroxide) is calculated as follows

    find the moles of Nitric acid = molarity x volume

    =29.5 x 0.175 = 5.163 moles of nitric acid

    write the equation for reaction

    HNO3 + NH4OH = NH4NO3 + H2O

    by use of mole ratio between HNO3 to NH4NO3 which is 1:1 the moles of NH4OH is also 5.163 moles

    molarity = moles/volume

    = 5.163 / 50=0.103 M is the molarity of the base
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