A radioactive nuclide that is used for radiation therapy for cancer has 33 neutrons and a mass number of 60. Which is the correct symbol for this nuclide?

To find the element, find the number of protons it has

Number of protons = Total mass - number of electrons

Number of protons = 60 - 33 = 27

Therefore the atomic number of the nuclide is 27

The 27th element is cobalt, therefore the answer is Cobalt or Co