Ask Question
19 April, 14:59

What is the entropy change for freezing 2.71 g of C2H5OH at 158.7 K? ∆H = - 4600 J/mol. Answer in units of J/K.

+4
Answers (1)
  1. 19 April, 18:24
    0
    -1.71 J/K

    Explanation:

    To solve this problem we use the formula

    ΔS = n*ΔH/T

    Where n is mol, ΔH is enthalpy and T is temperature.

    ΔH and T are already given by the problem, so now we calculate n:

    Molar Mass C₂H₅OH = 46 g/mol

    2.71 g C₂H₅OH : 46g/mol = 0.0589 mol

    Now we calculate ΔS:

    ΔS = 0.0589 mol * - 4600 J/mol / 158.7 K

    ΔS = - 1.71 J/K
Know the Answer?
Not Sure About the Answer?
Get an answer to your question ✅ “What is the entropy change for freezing 2.71 g of C2H5OH at 158.7 K? ∆H = - 4600 J/mol. Answer in units of J/K. ...” in 📙 Chemistry if there is no answer or all answers are wrong, use a search bar and try to find the answer among similar questions.
Search for Other Answers