Ask Question
25 July, 04:38

If 0.45 mols of MnO2 can react with 0.28 moles of HCl, how many moles of Cl2 could be produced

+2
Answers (1)
  1. 25 July, 08:26
    0
    MnO₂ + 4HCl = MnCl₂ + 2H₂O + Cl₂

    n (MnO₂) = 0.45 mols

    n (HCl) = 0.28 mols

    0.45 : 0.28 = 1 : 0.622

    the reaction equation 1:4

    the hydrogen chloride in the lack

    n (Cl₂) = n (HCl) / 4

    n (Cl₂) = 0.28/4=0.07 mols

    formed 0.07 mols of chlorine
Know the Answer?
Not Sure About the Answer?
Get an answer to your question ✅ “If 0.45 mols of MnO2 can react with 0.28 moles of HCl, how many moles of Cl2 could be produced ...” in 📙 Chemistry if there is no answer or all answers are wrong, use a search bar and try to find the answer among similar questions.
Search for Other Answers