What is the volume of 0.110 g of c2h2f4 vapor at 0.575 atm and 34.8◦c? answer in units of l?

To calculate the volume of the gas, we can use the ideal gas law equation.

PV = nRT

P - pressure - 0.575 atm x 101 325 Pa/atm = 58 261.9 Pa

V - volume

n - number of moles

C₂H₂F₄ - molar mass - 102 g/mol

Number of moles - 0.110 g / 102 g/mol = 0.00108 mol

R - universal gas constant - 8.314 Jmol⁻¹K⁻¹

T - temperature in Kelvin - 34.8 °C + 273 = 307.8 K

Substituting values in the equation,

58 261.9 Pa x V = 0.00108 mol x 8.314 Jmol⁻¹K⁻¹ x 307.8 K

V = 0.0000474 m³

V = 0.0474 L