A compound contains 38.7% K, 13.9% N, and 47.4% O by mass. What is the empirical formula of the compound?

A compound contains 38.7% K, 13.9% N, and 47.4% O by mass. What is the empirical formula of the compound?

Question

Chemistry

Braxton Callahan

12 January, 11:57

A compound contains 38.7% K, 13.9% N, and 47.4% O by mass. What is the empirical formula of the compound?

A compound contains 38.7% K, 13.9% N, and 47.4% O by mass. What is the empirical formula of the compound?

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Answers (1)

Know the Answer?

Stanley Hatfield · Answer 1

K - - - > 38.7 g / 39.1 g/mol = 0.99

N - - - > 13.9 g / 14.0 g/mol = 0.99

O - - - > 47.4 g / 16.0 g/mol = 2.96

Divide by smallest:

K - - - > 0.99 / 0.99 = 1

N - - - > 0.99 / 0.99 = 1

O - - - > 2.96 / 0.99 = 3

KNO3

A compound contains 38.7% K, 13.9% N, and 47.4% O by mass. What is the empirical formula of the compound?A compound contains 38.7% K, 13.9% N, and 47.4% O by mass. What is the empirical formula of the compound?

A compound contains 38.7% K, 13.9% N, and 47.4% O by mass. What is the empirical formula of the compound?

A compound contains 38.7% K, 13.9% N, and 47.4% O by mass. What is the empirical formula of the compound?