Calculate the height of a column of chloroform (CHCl3) that would be supported by atmospheric pressure. The density of chloroform is 1.483 g/cm3.

Pressure of liquids can be calculated using the following equation;

P = hρg

where h is the height of the liquid column

ρ - density of the liquid (kgm⁻³)

g - gravitational acceleration (ms⁻¹)

The column is supported by atmospheric pressure which is equal to 101 325 Pa

substituting the values in the equation

101 325 Pa = h x 1483 kgm⁻³ x 9.8 ms⁻²

h = 7.0 m

According to P formula:

P = H ρ g

when it is supported by atmospheric pressure

∴ P = atmospheric pressure = 1.01x10^5 N/m^2

H is the hight of the column

and when ρ is the density Kg/m^3 = 1.483g/Cm^3 = 1483Kg/m^3

g is the gravitational acceleration = 9.8Kg. m/S^2

so by substitution:

∴H = (1.01x10^5) / (1483 * 9.8)

=6.9 m