Barium nitrate reacts with aqueous sodium sulfate to produce solid barium sulfate and aqueous sodium nitrate. abigail places 20.00 ml of 0.500 m barium nitrate in a flask. how many grams of barium sulfate will be produced?

I will assume the chemical reaction equation is like this:

Ba (NO3) 2 + Na2SO4 - - - > 2 NaNO3 + BaSO4

For every 1 barium nitrate molecule used, there will be 1 barium sulfate formed. The number of molecule barium sulfate formed would be: 20.00 ml * 0.500 mol/1000ml * 1 = 0.01 mol

The mass of barium sulfate produced: 0.01mol * 233.38 g/mol = 2.3338 grams