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7 April, 19:06

Exactly one mole of an ideal gas is contained in a 2.00-liter container at 1,000 K. What is the pressure exerted by this gas?

Given: R = 0.08205 L · atm/K · mol

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  1. 7 April, 22:54
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    Use PV = nRT

    so P = nRT/V

    = 1 mole (0.08205 L atm/K mol) (1000K) / 2 L

    = 41 atm
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