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3 July, 11:41

A solution of malonic acid, h2c3h2o4, was standardized by titration with 0.1000 m naoh solution. if 21.55 ml of the naoh solution were required to neutralize completely 12.55 ml of the malonic acid solution, what is the molarity of the malonic acid solution?

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  1. 3 July, 14:15
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    The balanced chemical reaction between NaOH and malonic acid is as follows;

    H₂C₃H₂O₄ + 2NaOH - - > Na₂C₃H₂O₄ + 2H₂O

    Stoichiometry of H₂C₃H₂O₄ to NaOH is 1:2

    The number of moles of NaOH needed for complete neutralisation

    - 0.100 mol/L / 1000mL/L x 21.55 mL

    Therefore number of NaOH moles that have reacted = 0.002155 mol

    For complete neutralisation, number of malonic acid moles = (number of NaOH moles) / 2

    malonic acid moles reacted = 0.002155/2 mol

    Number of malonic acid moles in 12.55 mL = 0.002155/2 mol

    Therefore in 1000 mL volume = (0.002155/2 mol) / 12.55 mL x 1000 mL

    Molarity of malonic acid = 0.086 mol/L
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