A compound is found to contain 6.360 % silicon, 36.18 % bromine, and 57.46 % iodine by mass. what is the empirical formula for this compound?

Percentage of the compound,

silicon = 6.360 %

bromine = 36.18 %

iodine = 57.46 %

In 100 grams of compound we will have silicon = 6.36, bromine = 36.18, iodine = 57.46

Molar mass

silicon = 28.09, bromine = 79.90, iodine = 126.09

Calculating the moles,

silicon = 6.36 / 28.09 = 0.226

bromine = 36.18 / 79.90 = 0.452

iodine = 57.46 / 126.09 = 0.455

Divide with the lowest

silicon = 0.226 / 0.226 = 1

bromine = 0.452 / 0.226 = 2

iodine = 0.455 / 0.226 = 2

So the empirical formula would be SiBr2I2