Combustion analysis of a hydrocarbon produced 33.01 g co2 and 13.52 g h2o. calculate the empirical formula of the hydrocarbon.

Question

Chemistry

James Burns

27 July, 18:27

Combustion analysis of a hydrocarbon produced 33.01 g co2 and 13.52 g h2o. calculate the empirical formula of the hydrocarbon.

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Answers (1)

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Carlos Owens · Answer 1

Answer is: the empirical formula of the hydrocarbon is CH ₂.

Chemical reaction: C ₓHₐ + O₂ → xC + a/2H₂O.

m (CO ₂) = 33.01 g.

n (CO₂) = m (CO₂) : M (CO₂).

n (CO₂) = 33.01 g : 44.01 g/mol.

n (CO₂) = n (C) = 0.75 mol.

m (H₂O) = 13.52 g.

n (H₂O) = 13.52 g : 18 g/mol.

n (H₂O) = 0.75 mol.

n (H) = 2 · n (H₂O) = 1.5 mol.

n (C) : n (H) = 0.75 mol : 1.5 mol / 0.75 mol.

n (C) : n (H) = 1 : 2.