How many iron atoms contained in a 0.83 mole sample of iron

Answer: 5.00 x 10^23 atoms

Explanation:

Based on Avogadro's law:

1 mole of any substance has 6.02 x 10^23 atoms

So, 1 mole of Iron = 6.02 x 10^23 atoms

0.83 moles of Iron = Z atoms

To get the value of Z, cross multiply:

Z atoms x 1mole = (6.02 x 10^23 x 0.83)

Z = 5.00 x 10^23 atoms

Thus, there are 5.00 x 10^23 atoms of iron.