How many moles of sodium carbonate na2co3 are contained by 57.3 g of sodium carbonate

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Chemistry

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17 March, 19:47

How many moles of sodium carbonate na2co3 are contained by 57.3 g of sodium carbonate

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Marin Marshall · Answer 1

There are 0.54 moles of sodium carbonate are contained by 57.3 grams of sodium carbonate.

we can calculate number of moles in a compound by dividing number of grams of compound by the molar mass of the compound.

molar mass of sodium carbonate = 105.987 g/mol

now, 57.3 / 105.987 = 0.54 moles