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17 March, 20:05

A solution is formed by dissolving 36.5 g of urea, CO (NH2) 2, in 150.0 mL of water. What is the mole fraction of water in this solution? The density of water is 1.00 g / mL.

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  1. 17 March, 21:59
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    The mol fraction of water in this solution is 0.9319

    Explanation:

    Step 1: Data given

    Mass of urea = 36.5 grams

    Volume water = 150.0 mL

    Density of water = 1.00 g/mL

    Step 2: Calculate mass of water

    Mass water = density * volume

    Mass water = 1.00 g/mL * 150.0 mL

    Mass water = 150.0 grams

    Step 3: Calculate moles of water

    Moles H2O = mass H2O/molar mass H2O

    Moles H2O = 150.0 grams / 18.02 g/mol

    Moles H2O = 8.324 moles

    Step 4: Calculate moles urea

    moles urea = mass urea / molar mass urea

    Moles urea = 36.5 grams / 60.06 g/mol

    Moles urea = 0.608 moles

    Step 5: Calculate total moles

    Total moles = 8.324 moles + 0.608 moles

    Total moles = 8.932 moles

    Step 6: Calculate mol fraction

    Mol fraction of water = moles H2O / total moles

    Mol fraction H2O = 8.324 moles / 8.932 moles

    Mol fraction H2O = 0.9319

    The mol fraction of water in this solution is 0.9319
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