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3 August, 13:08

The isotope 206po has a half-life of 8.8 days. if you have 5.68 x 1025 atoms of this isotope, how long will it take for the sample to decay to 3.55 x 1024 atoms

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  1. 3 August, 16:34
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    By using the formula

    Activity final = activity initial x e (₋λ x time)

    λ = ln (2) / half life

    and,

    -ln (activity final/activity initial) =.693/8.8 days x time

    -ln[ (3.55x10 ²⁴) / (5.68x10²⁵) =.693/8.8 days x time

    2.77259 =.693/8.8 days x time

    2.77259 x 8.8 days =.693 x time

    24.3988 =.693 x time

    24.3988/.693 = time

    35.2075 = time

    time it will take to sample the decay is 35.2 days
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