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10 September, 18:24

What is the molecular formula of a compound containing 89% cesium (Cs) and 11% oxygen (O) with a molar mass = 298 g/mol?

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  1. 10 September, 21:42
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    M (Cs) = 133 g/mol

    M (O) = 16 g/mol

    M (CsxOy) = 298 g/mol

    w (Cs) = 0.89

    w (O) = 0.11

    CsxOy

    x=M (CsxOy) w (Cs) / M (Cs)

    x=298*0.89/133=2

    y=M (CsxOy) w (O) / M (O)

    y=298*0.11/16=2

    Cs₂O₂ cesium peroxide
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