The decomposition of dinitrogen pentoxide is described by the chemical equation 2 n2o5 (g) → 4 no2 (g) + o2 (g) if the rate of disappearance of n2o5 is equal to 1.80 mol/min at a particular moment, what is the rate of appearance of no2 at that moment?

Question

Chemistry

Kolby Stevenson

3 April, 09:08

The decomposition of dinitrogen pentoxide is described by the chemical equation 2 n2o5 (g) → 4 no2 (g) + o2 (g) if the rate of disappearance of n2o5 is equal to 1.80 mol/min at a particular moment, what is the rate of appearance of no2 at that moment?

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Derek Wise · Answer 1

The chemical reaction is

2 N₂O₅ (g) → 4 NO₂ (g) + O₂ (g)

In order to know the yield of Nitrogen Dioxide (NO ₂) from the Dinitrogen Pentoxide, you have to know the stoichiometric coefficients of the balanced reaction. The balancing of the reaction occurs because of the concept of the Law of Definite Proportions. The number of an element in the reaction must be equal in both sides. From the reaction, we can deduce that in every 2 moles of N₂O₅, 4 moles of NO₂ is produced. Therefore,

1.8 mol NO₂/min * 4 mol NO₂/2 mol N₂O₅ = 3.6

Thus, 3.6 moles of NO₂ is produced every minute.